Teaser and introduction goes here. Sample problem here.

The technique for finding the formula for the area of a trapezoid is the exact same technique we used for the triangles.

 To find the area of this trapezoid, we double it to create a familiar parallelogram.

 For this parallelogram, its base is the sum of the top and bottom bases of the trapezoid. So the area of the parallelogram is found like this

Area of parallelogram = $\large~(b_1 + b_2) • h$ = (2 + 6) • 3 = 24 square units

However, we only want the area of the trapezoid, so we have to divide the area of the parallelogram by 2 as such

Area of trapezoid = (Area of parallelogram) ÷ 2 = 24 ÷ 2 = 12 square units

To put this entire process on one line it would look like this

Area of trapezoid = (area of parallelogram) ÷ 2 = $\large~(b_1 + b_1)•h ÷ 2$

More often the formula looks like this

A = $\large~\frac{(b_1+b_2)•h}{2}$

Self-Check